or a cup of COLD STONE ice cream 1 contains 180 calories how there in cup? 82) i
ID: 3167467 • Letter: O
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or a cup of COLD STONE ice cream 1 contains 180 calories how there in cup? 82) if F= 50 degree Fahrenheit then find the temperature in degree Celsius many calories are Agood apher #3) wishes to ing taken with 100mA, 200ms and produces an intensity of 120mR if the the intensity to 240mR what should the new mAs value be? 3.b). A radiograph technique want to double the mA value while of 200 mR If you uses 100 mA and 0.1 sec and produces an intensity maintaining intensity what will the new technique be? hinhand120madei keserstripstraatare6#5)Anadographistakenusingan8.4musvalue high and120 mm thick, strips 6 cm high and 5 mm thick. Find the grid ratio. separated by aluminum and 120 mA current. What was the time in by #6) The control console is setto80mAand 150 ms, find the mAs value. #7) The control console is set to ½ second and 120 mA, find the mAs value. #8a) A good radiograph is taken with 36 mA, #8 b) A good radiograph is taken with 36 mA, is substituted. ghd tind the mAs value if a 6:1 grid 200ms, 16:1 grid and produces an intensity of 250 mR. Find the new mAs value if a 6:1 grid is substituted and the intensity is be maintained Le. kept constant at 250mR? g) A good radiograph is taken using 50 mAs #10 A radiograph is taken with control console and produces and intensity of 250 mR. If you settings of: 240 mA, 120 ms and produces an wish to decrease the intensity by a factor of 5 intensity of 180 mR. If the radiographer wants to double the intensity while keeping the current constant what must the new exposure time be in seconds? what should the new mAs value be? 11 b) A radiograph is taken with settings of: 120 mA, 400 #11 a) A radiograph is taken with settings of: ms and produces an intensity of 150 m 400 r., and produces an intensity of 120 mA, 150 mR. If the curent decreases to 60 mA while time is constant what will the new intensity be? to be kept constant what must the new t If the current decreases to 60 mA and intensity me be
Explanation / Answer
1) No. of calories in 2/3rd cup of ice crream =180
so, the No. of calories in a full cup of ice cream = 180x3/2=270
Therefore the No. of calories in 1/2 cup of ice cream = 270x1/2=135
2) given temperature F= 590F
To convert it this temperature into degrees centegrade = (F-32)x5/9 = (59-32)x5/9 = 27x5/9 =150C
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