Suppose this same jogger decides to go to a local park and use one of the paths
ID: 3168981 • Letter: S
Question
Suppose this same jogger decides to go to a local park and use one of the paths there for the workout routine one day each week. This path is a gently sloping one that winds its way to the top of a hill. 6. If the jogger can run at an average speed of 5.5 miles per hour up the slope and 6.5 miles per hour going down the slope, how long, in hours, will it take for the jogger to cover 2 miles by going uphill for 1 miles and then returning 1 mile back down the hil? [Give an exact answer expressed as a fraction in simplest terms and then give a decimal approximation correct to three decimal places]Explanation / Answer
Total distance to be covered = 2 miles; Of which 1 mile is uphill and 1 mil is downhill;
Speed up hill = 5.5 miles per hour; Distance to be covered uphill = 1 mile; So, time taken will be = distance/ speed
tu = 1/5.5 = 1/5.5 hours
Speed downhill = 6.5 miles/hour; Distance to be covered downhill=1 mile; So, time taken will be = distance/ speed
td = 1/6.5 = 1/6.5 hours
Total time to be takn = t = tu + td = 1/5.5 + 1/6.5 = 6.5+5.5 / (6.5)(5.5) = 12/(6.5*5.5) = 12/35.75 = 1200/3575 hours
Thus, total time taken in hours = 1200/3575 hours
In decimal form total time taken = 0.3356 ~= 0.336 hours
Thus, total time taken in 3 decimal places = 0.338 hours
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