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My Notes Ask Your Teacher 2· 4 1/3 points Previous Answers HarMathAp11 9.8.041 T

ID: 3169898 • Letter: M

Question

My Notes Ask Your Teacher 2· 4 1/3 points Previous Answers HarMathAp11 9.8.041 The daily sales S (in thousands of dollars) that are attributed to an advertising campaign are given by 17 s-15+ t+2 2) where t is the number of weeks the campaign runs. (a) Find the rate of change of sales at any time t (b) Use the second derivative to find how this rate is changing at t 15. (c) Interpret your result in part (b) The rate of change of the rate of change in sales (after 15 weeks) is the amount given in part (b). Need Help? Read. I Submit Answer Save Progress Practice Another Version

Explanation / Answer

a) s' = -3(t + 2)-2 - (-17(t + 2)-3)

        = -3(t + 2)-2 + 17(t + 2)-3

b) s'' = (-3 * (-2))(t + 2)-3 + 17 * (-3)(t + 2)-4

        = 6(t + 2)-3 - 51(t + 2)-4

        = 6/(t + 2)3 - 51/(t + 2)4

At t = 15

s'' = 6/(15 + 2)3 - 51/(15 + 2)4

    = 6/(17)3 - 51/(17)4

   = (6 * 17 - 51)/(17)4

   = 51/(17)4

   = 3/(17)3

   = 3/4913

   =

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