My Notes Ask Your Teacher 2· 4 1/3 points Previous Answers HarMathAp11 9.8.041 T
ID: 3169898 • Letter: M
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My Notes Ask Your Teacher 2· 4 1/3 points Previous Answers HarMathAp11 9.8.041 The daily sales S (in thousands of dollars) that are attributed to an advertising campaign are given by 17 s-15+ t+2 2) where t is the number of weeks the campaign runs. (a) Find the rate of change of sales at any time t (b) Use the second derivative to find how this rate is changing at t 15. (c) Interpret your result in part (b) The rate of change of the rate of change in sales (after 15 weeks) is the amount given in part (b). Need Help? Read. I Submit Answer Save Progress Practice Another VersionExplanation / Answer
a) s' = -3(t + 2)-2 - (-17(t + 2)-3)
= -3(t + 2)-2 + 17(t + 2)-3
b) s'' = (-3 * (-2))(t + 2)-3 + 17 * (-3)(t + 2)-4
= 6(t + 2)-3 - 51(t + 2)-4
= 6/(t + 2)3 - 51/(t + 2)4
At t = 15
s'' = 6/(15 + 2)3 - 51/(15 + 2)4
= 6/(17)3 - 51/(17)4
= (6 * 17 - 51)/(17)4
= 51/(17)4
= 3/(17)3
= 3/4913
=
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