Suppose that gene b is sex linked (to the x chromosome)recessive and LETHAL in t
ID: 3170 • Letter: S
Question
Suppose that gene b is sex linked (to the x chromosome)recessive and LETHAL in the womb. A man marries a woman who isheterozygous for this gene a) if this couple had many children, what would be thepredicted sex ratio of these children? b) is it possible for the man to be a carrier of this lethalgene? c) was the woman's mother a carrier of gene b? 2. a man and a woman both have normal color vision, they have twochildr en, a son with normal vision and a dau ghter which has redgreen color blindness, a sex linked (to the x chromosome) recessivegene. the man sues his wife for divorce on grounds of infidelity.if you were his attorney, could you use this evidence in your case?if yes, which child provide the evidence of infidelity son ordaughter? (show a punnett square) Suppose that gene b is sex linked (to the x chromosome)recessive and LETHAL in the womb. A man marries a woman who isheterozygous for this gene a) if this couple had many children, what would be thepredicted sex ratio of these children? b) is it possible for the man to be a carrier of this lethalgene? c) was the woman's mother a carrier of gene b? 2. a man and a woman both have normal color vision, they have twochildr en, a son with normal vision and a dau ghter which has redgreen color blindness, a sex linked (to the x chromosome) recessivegene. the man sues his wife for divorce on grounds of infidelity.if you were his attorney, could you use this evidence in your case?if yes, which child provide the evidence of infidelity son ordaughter? (show a punnett square)Explanation / Answer
a) The man's genotype is XB Y. The woman is heterozygous so she is XBXb Cross | XB Y XB | XB XB XB Y Xb | XB Xb Xb Y Half the males exibit the lethal gene thus the ratio of females tomales is 2:1 b) The man can't be a carrier for the gene since he only has one Xchromosome. If he carried the lethal gene he would have died in thewomb c) She was a carrier since she was heterozygous for the gene b. 2. You could use this evidence in your case. The man has normal visionso his genotype is XG Y (where G is normal vision) The woman has normal vision but her daughter inherited onerecessive Xg from her so genotype is XG Xg. The Punnet Square for this is as follows XG Y XG | XG XG XG Y Xg | XG Xg Xg Y The daughter has genotype Xg Xg which is not a possible combinationfor this couple which indicates that her true father is colorblind. Thus the daugher can be used as evidence ofinfidelity.
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