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Chamberlain Co X P Take a Test Ties X a Upload Document x Course Home Pag X Want

ID: 3170145 • Letter: C

Question

Chamberlain Co X P Take a Test Ties X a Upload Document x Course Home Pag X Want To Make Su X C Secure https:// com www.mathxl Tiesha McGrew & Applied Managerial Statistics (100) Quiz: Final Exam Time Remaining: 02:23:26 Submit Quiz This Question 10 pts 15 of 24 (22 complete) This Quiz 250 pts possible Find the probability and interpret the results. convenient, use technology to find the probability. The population mean annual salary for environmental compliance specialists is about $62,000. A random sample of 44 specialists is drawn from this population. What is the probability that the mean salary of the sample is less than $58,500? Assume o $6,000 The probability that the mean salary of the sample is less than $58,500 is (Round to four decimal places as needed.) Interpret the results. Choose the correct answer below. O A. Only 0.01% of samples of 44 specialists will have a mean salary less than $58,500. This is an extremely unusual event. O B. About 1% of samples of 44 specialists will have a mean salary less than $58,500. This is not an unusual event. O C. Only 1% of samples of 44 specialists will have a mean salary less than $58,500. This is an extremely unusual event. O D. About 0.01% of samples of 44 specialists will have a mean salary less than $58,500. This is not an unusual event. Click to select your answer(s) 4:37 AM Ask me anything 2/22/2017

Explanation / Answer

Here, mean = 62000 , Standard deviation = 6000 sqrt(44) = 904.534

X = 58500

By normal distribution formula,

P( X < 58500) = (X - mean) / SD

= ( 58500 - 62000) 904.534

= -3.8694

Now, we need to find P( Z < -3.8694) by using z standard right tail, we get

P( X < 58500) = 0.0001

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