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Sheila\'s doctor is concerned that she may suffer from gestational diabetes (hig

ID: 3170233 • Letter: S

Question

Sheila's doctor is concerned that she may suffer from gestational diabetes (high blood glucose levels during pregnancy). There is variation both in the actual glucose level and in the blood test that measures the level. A patient is classified as having gestational diabetes if the glucose level is above 140 milligrams per deciliter (mg/dl) one hour after a sugary drink is ingested. Sheila's measured glucose level one hour after ingesting the sugary drink varies according to the Normal distribution with = 123 mg/dl and = 10 mg/dl. What is the level L such that there is probability only 0.05 that the mean glucose level of 2 test results falls above L for Sheila's glucose level distribution? (Round your answer to one decimal place.)

Below is what someone else did to get the correct answer, but I didn't understnad how to get my answer. can someone help please

Solution: Given: Mean 127 Standard deviation 10 Find the Sheila's glucose level one hour after ingesting the sugary drink The z-score formula is 140-127 POX 140) P Z 10 p z 140-127 10 13 1-P Z 10 1- (Z

Explanation / Answer

here for 0.05 probabilty on upper tail, at 95% CI, value of z=1.6449

hence level L =mean +z*std deviation =123+1.6449*10=139.449~139.4

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