A digital transmission carries a randomly mixed set of voice packets. The occurr
ID: 3170602 • Letter: A
Question
A digital transmission carries a randomly mixed set of voice packets. The occurrence statistics of packets are designated in 6 groups. The number of occurrences of each group and the corresponding random value of the associated bit rates are as follows: Determine the following of the RV (Bit rate R_i): (a) Find the upper and lower bounds of the average performance of the RV (b) State with reason the most appropriate mean value that describes the average performance of the bit rate (c) Find the expected mean, median and mode A digitized video transmission carries a randomly mixed set of video packets. The occurrence statistics of the packets are designated in 6 groups. The video transmission involves streaming of packets wherein the statistics of occurrence of bit rate in each packet depends strongly on bit-rate values in consequent packets streamed. The number of occurrences of each group and the corresponding random value of the associated bit rates are as follows: Determine the following of the RV (Bit rate - R_i): I. Find the upper and lower bounds of the average performance of the RV II. State with reason the most appropriate mean value that describes the average performance of the bit rate III. Find the expected mean, median and modeExplanation / Answer
Q.1
Upper bound of the average performance = 4160
Lower bound of the average performance = 2850
Mean Value of the Performance = (4160 + 3658 + 3300 + 3596 + 2850 + 3660)/6 = 3537.333
In the calculation of the mean, these groups are interested in the performance.
The median is at the middle of an ordered (ranked) data set and is a useful measure for ordinal variables.
Strictly speaking, the mean only makes sense for interval and ratio scales of measurement
Median = (3596 + 3658 )/2= 3627
Hope this will help you. Thanks
Event Enumerated Bit Rates in Kbps No. of occurances Performance 1 64 65 4160 2 59 62 3658 3 60 55 3300 4 62 58 3596 5 57 50 2850 6 61 60 3660Related Questions
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