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Suppose we have a binomial experiment in which success is defined to be a partic

ID: 3171116 • Letter: S

Question

Suppose we have a binomial experiment in which success is defined to be a particular quality or attribute that interests us.

(a) Suppose n = 25 and p = 0.39. Can we approximate p^ by a normal distribution? Why? (Use 2 decimal places.)



---Select---       Yes       No

Yes

,  p^   ---Select---       cannot       can

can

be approximated by a normal random variable because   ---Select---       both np and nq exceed       np and nq do not exceed       np does not exceed       nq exceeds       np exceeds       nq does not exceed

both np and nq exceed

.

What are the values of p^ and p^? (Use 3 decimal places.)



(b) Suppose n = 25 and p = 0.15. Can we safely approximate p^ by a normal distribution? Why or why not?
---Select---       Yes       No

No

,  p^   ---Select---       can       cannot

cannot

be approximated by a normal random variable because   ---Select---       nq does not exceed       nq exceeds       np exceeds       np and nq do not exceed       np does not exceed       both np and nq exceed

np does not exceed

.

(c) Suppose n = 48 and p = 0.35. Can we approximate  p^ by a normal distribution? Why? (Use 2 decimal places.)



---Select---       Yes       No

Yes

,  p^   ---Select---       cannot       can

can

be approximated by a normal random variable because   ---Select---       np does not exceed       nq exceeds       both np and nq exceed       np exceeds       nq does not exceed       np and nq do not exceed

both np and nq exceed

.

What are the values of p^ and p^? (Use 3 decimal places.)

np = nq =

Explanation / Answer

a)np=25*0.39=9.75

nq=15.75

no cannot be  approximated by a normal random variable because np does not exceed

b)np=25*0.15=3.75

nq=25*0.85=21.25

No cannot be approximated by a normal random variable because np does not exceed

c)np=48*0.35=16.8

n1=48*0.65=31.2

yes

can

be approximated by a normal random variable because both np and nq exceed

here p =np=16.8

p =(np(1-p))1/2=3.305

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