Die #2 The sum of the number 6 from die #1 and the number 3 from die #2 Notes 1.

Question

Die #2 The sum of the number 6 from die #1 and the number 3 from die #2 Notes 1. The bold numbers represent each side of each die. 2. The italicized numbers represent the sum of the values from each die. 3. Not all sums have been included in the table-feel free to fill in the rest. 4. The italicized numbers in the red shaded cells indicate a sum with an addend of 1. Therefore, the red shaded sums will reduce your turn's score to 0. Thus, they correspond to the event A, "a failed roll". 5. The italicized numbers in the green shaded cells indicate a sum in which no addend is the number 1. Therefore, they correspond to the event B, "a successful roll. 6. Warningu do not double-count the red shaded sum 2 when calculating POA). 7. Hinta Consider total number of shaded cells (both red and green) when forming your denominator for POA) and P(B). 8. For problems 9 & 12-15, use the formula IP (B) 8k, where k is the number of rolls, to calculate the expected value

Explanation / Answer

6)

P(A) = (total no of possibilities with 1) / (total possibilities)

total no of possibilities with 1 = all red blocks = 5+6= 11

total possibilities = 62 = 36

P(A) = 11/36=0.3056

7)

P(B) = 1-P(A) = (1-0.3055) =0.6944

8)

in Successful role possible ot come

no no of timees that appear

4,12 1

5 ,11 2

6,10 3

7,9 4

8 5

mean = (8*5 + 4*(7+9) +3*(6+10)+2*(5+11) +4+12) /25 =8

que 10,11)

in constutive to times we will calculate probability of success

probability of success in continuous 2 times = 25/36*25/36= 0.4822

probability of failour= 1- p(success) = 1-.4822= 0.5178

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