Below are 2-sample t-test and tests for equal for an experiment looking at an al

Question

Below are 2-sample t-test and tests for equal for an experiment looking at an alternative process condition. What can you conclude about the mean and the variation between the two process conditions? Explain your reasoning and describe the probability that your conclusion is incorrect. 4. he mean for the se two sample are CI mean is sao of while C2 mean s 462.6 we can see than CI has more sample sets than ci giving us a better Idea of our data onio were The mean might fall. We fail rejet the null Hypothesis Two-Sample T-Test and CI: C1, C2 Two-sample T for C1 vs C2 N Mean StDev Mean C1 78 580 415 47 c2 4 462.6 58 29 Difference mu (C1) mu (C2) Estimate for difference 117.8 958 CI for difference (4.7, 230. 9) Test of difference 0 vs not T-value 2.13 P-Value 0.042 DE 30 Test for Equal Variances for C1, C2 F-Test Test Statistic 49,90 p-Value C1 Levene s Test Test Statistic 5.08 P-Value 0.027 C2 95% Bonferroni Confidence Intervals for StDevs o 500 750 1000 1280 1500 1750 Data

Explanation / Answer

Result:

The mean for c1 is 580 and mean for c2 is 462.6. The calculated t=2.13, P=0.042 which is < 0.05 level of significance. This shows that there is significant mean difference.

Test for equality of variance ( F test and Levene test) shows that P value is < 0.05 level. We conclude that there is significant differences in variance between c1 and c2 . Therefore one assumption for comparing two means, equality of variance assumption is violated.

Therefore conclusion in comparing means of c1 and c2 is incorrect.

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