ONLY NEED HELP WITH PART C Viscosity, V 13.300 14.500 15.300 15.300 14.300 14.80
ID: 3172143 • Letter: O
Question
ONLY NEED HELP WITH PART C
Viscosity, V
13.300
14.500
15.300
15.300
14.300
14.800
15.200
14.500
14.600
14.100
14.300
16.100
13.100
15.500
12.600
14.600
14.300
15.400
15.200
16.800
14.900
13.700
15.200
14.500
15.300
15.600
15.800
13.300
14.100
15.400
15.200
15.200
15.900
16.500
14.800
15.100
17.000
14.900
14.800
14.000
15.800
13.700
15.100
13.400
14.100
14.800
14.300
14.300
16.400
16.900
14.200
16.900
14.900
15.200
14.400
15.200
14.600
16.400
14.200
15.700
16.000
14.900
13.600
15.300
14.300
15.600
16.100
13.900
15.200
14.400
14.000
14.400
13.700
13.800
15.600
14.500
12.800
16.100
16.600
15.600
Viscosity, V
13.300
14.500
15.300
15.300
14.300
14.800
15.200
14.500
14.600
14.100
14.300
16.100
13.100
15.500
12.600
14.600
14.300
15.400
15.200
16.800
14.900
13.700
15.200
14.500
15.300
15.600
15.800
13.300
14.100
15.400
15.200
15.200
15.900
16.500
14.800
15.100
17.000
14.900
14.800
14.000
15.800
13.700
15.100
13.400
14.100
14.800
14.300
14.300
16.400
16.900
14.200
16.900
14.900
15.200
14.400
15.200
14.600
16.400
14.200
15.700
16.000
14.900
13.600
15.300
14.300
15.600
16.100
13.900
15.200
14.400
14.000
14.400
13.700
13.800
15.600
14.500
12.800
16.100
16.600
15.600
(a) Given the sample data, viscosity of sample fluids produced at our plant (entered as a table so you can copy it into Excel easily), find the mean, median, mode, standard deviation and variance of the sample. Mean: 14.89875 Median: 14.9 Mode: 15.2 Standard Deviation: 0.9803763 Variance: 0.96113766 (b) If the process is supposed to produce viscosities of 15.0 t/-1.5, comment on how well the process is working The process is working just fine, as the standard deviation for this sample is only about 0.98 which is under the given 1.5 standard deviation listed above. (c) If we wanted to define a variable (X, as a function of viscosity) that has a mean of 0 and a standard deviation of 1, what would it be? Demonstrate mathematically that you get the correct mean and standard deviation. What value would this have to our analysis of data? for part c remember that and N-1Explanation / Answer
c)
Z = (X- E(X) )/sd (X) has mean 0 , and variance = 1
hence
Z = (V - 14.8975)/0.9803763 ,
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