Natural cork in wine bottles is subject to deterioration, and as a result wine i
ID: 3172216 • Letter: N
Question
Natural cork in wine bottles is subject to deterioration, and as a result wine in such bottles may experience contamination. The article "Effects of Bottle Closure Type on Consumer Perceptions of Wine Quality" (Amer. J. of Etiology and Viticulture, 2007: 182-191) reported that, in a tasting of commercial chardonnays, 16 of 91 bottles were considered spoiled to some extent by cork-associated characteristics. Does this data provide strong evidence for concluding that more than 15% of all such bottles are contaminated in this way? Carry out a hypothesis test (clearly write down each of the 4 steps for the hypothesis test) to decide whether more than 15% of all such bottles are contaminated. Use significance level of 0.05 Verify the test you use is appropriate. For example, if you use a t-test or z-test, verify the corresponding conditions.Explanation / Answer
Part A
Here, we have to use z test for population proportion.
The null and alternative hypothesis for this test is given as below:
Null hypothesis: H0: p = 0.15
Alternative hypothesis: Ha: p > 0.15
The test statistic formula is given as below:
Z = (P – p) / sqrt(pq/n)
Where, P = sample proportion, p = population proportion, q = 1 – p, n = sample size
For the given data we have
Alpha = 0.05
Number of items of interest = x = 16
Sample size = n = 91
Sample proportion = 16/91 = 0.175824
Standard error = sqrt(pq/n) = sqrt(0.15*0.85/91) = 0.0374
Z = (0.175824 – 0.15) / 0.0374
Z = 0.6899
P-value = 0.2451
P-value > Alpha value
So, we do not reject the null hypothesis
There is insufficient evidence that more than 15% of all such bottles are contaminated.
Part b
Here, z test is appropriate.
Because two conditions are satisfied as below:
np = 91*0.15 = 13.65 > 5
nq = 91*0.85 = 77.35 > 5
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