Salmon Weights (Raw Data, Software Required): Assume that the weights of spawnin
ID: 3173007 • Letter: S
Question
Salmon Weights (Raw Data, Software Required):
Assume that the weights of spawning Chinook salmon in the Columbia river are normally distributed. You randomly catch and weigh 15 such salmon. The data is found in the table below. You want to construct a 99% confidence interval for the mean weight of all spawning Chinook salmon in the Columbia River. You will need software to answer these questions. You should be able to copy the data directly from the table into your software program.
No, because 24 is above the lower limit of the confidence interval.
Yes, because 24 is below the lower limit of the confidence interval.
No, because 24 is below the lower limit of the confidence interval.
Yes, because 24 is above the lower limit of the confidence interval.
Because we do not know the distribution of the parent population.
Because the sample size is greater than 10.
Because the sample size is less than 100.
Because the parent population is assumed to be normally distributed.
Salmon Weight
1 26.7
2 25.8
3 37.0
4 27.6
5 19.9
6 23.5
7 34.2
8 26.8
9 24.5
10 27.8
11 33.5
12 28.7
13 29.8
14 29.3
15 32.5
(a) What is the point estimate for the mean weight of all spawning Chinook salmon in the Columbia River? Round your answer to 2 decimal places.
pounds
(b) Construct the 99% confidence interval for the mean weight of all spawning Chinook salmon in the Columbia River. Round your answers to 2 decimal places.
< <
(c) Are you 99% confident that the mean weight of all spawning Chinook salmon in the Columbia River is greater than 24 pounds and why?
No, because 24 is above the lower limit of the confidence interval.
Yes, because 24 is below the lower limit of the confidence interval.
No, because 24 is below the lower limit of the confidence interval.
Yes, because 24 is above the lower limit of the confidence interval.
(d) Recognizing the sample size is less than 30, why could we use the above method to find the confidence interval?
Because we do not know the distribution of the parent population.
Because the sample size is greater than 10.
Because the sample size is less than 100.
Because the parent population is assumed to be normally distributed.
Salmon Weight
1 26.7
2 25.8
3 37.0
4 27.6
5 19.9
6 23.5
7 34.2
8 26.8
9 24.5
10 27.8
11 33.5
12 28.7
13 29.8
14 29.3
15 32.5
Explanation / Answer
a) point estimate for the mean weight of all spawning Chinook salmon in the Columbia River=28.507
b)for 14 df and 99% CI, t=2.9768
hence confidence interval =mean +/- t*std error =25.083 ; 31.930
c)Yes, because 24 is below the lower limit of the confidence interval.
d)Because the parent population is assumed to be normally distributed.
X 26.700 25.800 37.000 27.600 19.900 23.500 34.200 26.800 24.500 27.800 33.500 28.700 29.800 29.300 32.500 mean(X) 28.507 std deviation(S) 4.454 std error =S/(n)1/2 1.150Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.