A nutritionist wants to determine how much time nationally spend eating and drin

Question

A nutritionist wants to determine how much time nationally spend eating and drinking. Suppose for a random sample of 958 people age 15 or older, the mean amount of time spent eating or drinking per day is 1.23 hours with a standard deviation of 0.69 hours. Complete part(s) through (d) below Select the correct choice below and fill in the answer boxes, if applicable, in your choice. (Type integers or decimals rounded to three decimal places as needed. Use ascending order.) There A 95% probability that the mean amount of time spent eating or drinking per day is between and hours The nutritionist is 95% confident that the amount of time spent eating or drinking per day for any individual is between and hours. The nutritionist is 95% confident that the mean amount of time spent eating or drinking per day is between and hours. The requirements for constructing a confidence interval are not satisfied. Could the interval be used to estimate the mean amount of time a 9-year-old spends eating and drinking each day? Explain. Yes; the interval is about individual time spent eating or drinking per day and can be used to find the mean amount of time a 9-year-old spends eating and

Explanation / Answer

here std error of the mean =std deviation/(n)1/2 =0.69/(958)1/2 =0.0223

for 95% CI, z=1.96

hence confidence interval =mean +/- z*std error =1.186 ; 1.274

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