Probability that a person is carrying a Visa Card is .60, P(V) & AmEx is .20, P(

Question

Probability that a person is carrying a Visa Card is .60, P(V) & AmEx is .20, P(A). Probability that a person carries both is .15. Calculate the probability that a person will carry at least one of the cards. Use the matrix notation - Calculate Joint Probabilities, - Marginal - Conditional probabilities (show them clearly) P (a random person doesn' t have both of the cards) =? P (a person has Visa card) =? Given that a person has Amex card, calculate the P (he has also visa)? (Draw Tree Diagram also to show conditional probabilities) Probability that a random person will carry at least one of the cards

Explanation / Answer

i)probability that a person does not have both the cards =1-P(VUA)=1-0.65=0.35

ii)=0.6

(iii)P(V|A)=P(V&A)|P(A)=0.15/0.2=0.75

(iv)probabilty that person carries at least =P(V)+P(A)-P(V &A) =0.6+0.2-0.15=0.65

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