Condi ionH Probability tha a is carrying a visa Catd .60, Prvu & AmEx is 20, Pci
ID: 3174774 • Letter: C
Question
Explanation / Answer
(i) probabilty that a person have at least one card =P(VUA) =P(V)+P(A)-P(A V) =0.6+0.2-0.15=0.65
hence probability does not have both of the cards =1-P(VUA)=1-0.65=0.35
(ii) P(V)=0.6
(iii)P(V|A) =P(V&A)/P(A)=0.15/0.2=0.75
(iv) probabilty that a person have at least one card =P(VUA) =P(V)+P(A)-P(A V) =0.6+0.2-0.15=0.65
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