Need part B completed with the percentile answers Do Homework Rachael Hamilton G

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Need part B completed with the percentile answers

Do Homework Rachael Hamilton Google Chrome questionld 16&flushed; false&cld; cent erwin yes Secure I https/www.mathxl.com/Student/PlayerHomework.aspx?homeworkld 4103053358 STA220 Homework: Section 2.5 Score: 0 of 1 pt 20 of 23 (20 complete 2.5.48 The life spans of a species of fruitfy have a bell-shaped distribution. with a mean of 35 days and a standard deviation of 4 days. (a) The life spans of three randomly selected fruit fies are 37 days, 34 days, and 47 days. Find the z-score that corresponds to each life span. Determine whether any ofthese life spans are unusual. (b) The life spans of three randomly selected fruit fles are 47 days, 43 days, and 39 days. Using the Empincal Rule,Mnd the percentile that corresponds to each life span. a) The z-score corresponding a life span of 37 days is 0.5 Type an integer or a decimal rounded to two decimal places as needed The 2-score corresponding a life span of 34 days is 0.25 pe an integer or a decimal rounded to two decimal places as needed.) The z-score corresponding a life span of 47 days is 3 (Type an intege a decimal rounded to two decimal places as needed Select all of the life spans that are unusual 47 days B. 34 days C. 37 days D. None of the life spans are unusual. (b) Determine the percentiles using the Empirical Rule The 47 day fruit fy corresponds to the th percentile. The 43 day fruit corresponds to the th percentile. thy The 39 day fruit fly comesponds to the th percent (Type an intege a decimal Enter your answer in the edit fields and then click Check Answer. All parts showing Ask me anything Rachael Hamilton & 3/6/17 11:27 PM Save HW Score: 78.99%, 18.17 of 23 pts E Question Help 11:27 PM 3/6/2017

Explanation / Answer

Part B

68–95–99.7 rule is an emperical rule used to determine probabilities that are within a band of 1, 2 and 3 standard deviations.

Mean = 35

standard deviation = 4

Probability within 3 standard deviations = 0.9973

47 is three standard deviation towards the right from mean. So, 47th day corresponds to 0.5+0.9973/2 = 0.9987 = 99.87th percentile

Probability within 2 standard deviations = 0.9545

43 is one standard deviation towards the right from mean. So, 43rd day corresponds to 0.5+0.9495/2 = 0.9748 = 97.48th percentile

Probability within 1 standard deviation = 0.6627

39 is one standard deviation towards the right from mean. So, 39th day corresponds to 0.5+0.6627/2 = 0.8314 = 83.14th percentile

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