The time needed for college students to complete a certain paper and pencil maze

Question

The time needed for college students to complete a certain paper and pencil maze follows a Normal distribution, with a mean of 70 seconds and a standard deviation of 15 seconds. You wish to see if the mean time His changed by meditation, so you have a group of 9 college students meditate for 30 minutes and then complete the maze. You compute the average vector x of their times to complete the maze and will use this information to test the hypotheses H0; mu = 70, Ha; mu notequalto 70 If you observe a sample mean completion time of vector x = 78.55, based on the p-value from the test which conclusion is the most appropriate. There is no evidence that the meditation changed the time to complete the maze. There is convincing evidence that the meditation changed the time to complete the maze. There is moderately suggestive evidence that the meditation changed the time to complete the maze. There is suggestive but inconclusive evidence that the meditation changed the time to complete the maze.

Explanation / Answer

here std error =std deivation/(n)1/2 =15/(9)1/2=5

hence test stat z=(X-mean)/std erorr =(78.55-70)/5=1.71

for above p value=0.0872

as p value is higher then 0.05 level

there is suggestive but inconclusive evidence that the meditation changed the time to complete the maze

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