A real estate agent is showing homes to a prospective buyer. There are ten homes

Question

A real estate agent is showing homes to a prospective buyer. There are ten homes in the desired price range listed in the area. The buyer has time to visit only four of them. If four of the homes are new and six have previously been occupied and if the four homes to visit are randomly chosen, what is the probability that all four are new? (The same answer results regardless of whether order is considered.)

4. A real estate agent is showing homes to a prospective buyer. There are ten homes in the desired price range listed in the area. The buyer has time to visit only four of them. If four of the homes are new and six have previously been occupied and if the four homes to visit are randomly chosen what is the probability that all four are new? (The same answer results regardless of whether order is considered

Explanation / Answer

No of ways in which 4 homes can be chosen out of 10 = 10C4 = 10!/(4!x(10-4)!) = 210

In these 210 different sets, only 1 set includes all four new homes

So, P(all four are new) = 1/210 = 0.00476

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.