A college administration has conducted a study of 200 randomly selected students

Question

A college administration has conducted a study of 200 randomly selected students to determine the relationship between satisfaction with academic advisement and academic success. They obtained the following information: Of the 70 students that are on academic probation, 32 students are not satisfied with advisement; however only 20 of the students not on academic probation are dissatisfied with advisement. Assume a student is selected at random.

a) What is the probability that the student is satisfied with advisement?

b) What is the probability that the student is on academic probation and is satisfied with advisement?

c) What is the probability that the student is not on academic probation and is satisfied with advisement?

Explanation / Answer

Tabulate the results.

a. P(student is satisfied with advisement)=148/200 (use classical probability, P(A)=# of counts in A/Total counts)

=0.74 (ans)

b. P(Academic probation AND satisfied with advisement)=P(academic probation)*P(satisfied with advisement)

=70/200*148/200 [use general multiplication rule, P(A and B)=P(A)*P(B)]

=0.259 (ans)

c. P(student not on academic probation and is satisfied with advisement)=P(student not on academic probation)*P(satisfied with advisement)

=130/200*148/200

=0.481 (ans)

Academic probation Yes No Total Satisfied with advisement Yes 38 110 148 No 32 20 52 Total 70 130 200

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