Perform a one-tailed test. Then fill in the table below. Carry your intermediate

Question

Perform a one-tailed test. Then fill in the table below.

Carry your intermediate computations to at least three decimal places and round your answers as specified in the table. (If necessary, consult a list of formulas.)

1. The null hypothesis: H0:

2. The alternative hypothesis: H1:

3. The type of test statistic: (Choose one): Z OR t OR Chi square OR F

If applicable, what are the degrees of freedom?

4. The value of the test statistic:
(Round to at least three decimal places.)

6. Can we conclude that the proportion of depressed individuals taking Resithan who find relief is less than the proportion taking Exemor who find relief? : Yes OR No

Carry your intermediate computations to at least three decimal places and round your answers as specified in the table. (If necessary, consult a list of formulas.)

Explanation / Answer

1.)

Ho: P1 P2

2.)

H1: P1 < P2

3.)

This is Z test

4.)

z = (p1^ -p2^) / SE (p1-p2)

SE (p1-p2) = Ö[PQ*((1/n1) +(1/n2))

P = (x1+x2)/(n1+n2)

Q = 1 – P

x1 = 192

n1   =567

x2 = 206

n2 = 508

p1^ = 192 / 567 = 0.3386

p2^ = 206/508 = 0.4055

P = (x1+x2)/(n1+n2) = (192+206)/(567+508) = 0.3702

Q = 1 – P = 1 – 0.3702 = 0.6298

z = (0.3386 -0.4055)/Ö[(0.3702*0.6298)*((1/567)+(1/5080)]

= -2.267

The value of the test statistics is -2.267

5.)

The critical value for 5% level of significance from normal table we get as -1.645

6.)

The test statistics is less than the critical value (-2.267 < -1.645); the null hypothesis can be rejected at 5% level of significance.

Answer: Yes

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