In the game of blackjack as played in casinos in Las Vegas, Atlantic City, Niaga

Question

In the game of blackjack as played in casinos in Las Vegas, Atlantic City, Niagara Falls, as well as many other cities, the dealer has the advantage. Most players do not play very well. As a result, the probability that the average player wins a hand is about 0.37. Find the probability that an average win twice in 5 hands. Probability = 10 or more times in 25 hands. Probability = There are several books that teach blackjack players the "basic strategy" which increases the probability old winning any hand to 0.49. Assuming that the player plays the basic strategy, find the probability that he or she wins twice in 5 hands. Probability = 10 or more times in 25 hands. Probability =

Explanation / Answer

p win = .37

a. P(2 times in 5 hands) = 5C2(.37^2)(1-.37)^3 = .2423
b. P( more than 10 out of 25 times)= 0.4517

Now, p = .49
c. P(2 times in 5 hands) = = 5C2(.49^2)(1-.49)^3 = .3185
d. P(more than 10 out of 25 times)= 0.8646

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