In a random sample of 985 students from a large public university, it was found
ID: 3176753 • Letter: I
Question
In a random sample of 985 students from a large public university, it was found that 465 of the students changed majors during their college years. Give a 95% confidence interval for the proportion of students at this university who change majors. (Round your answers to four decimal places.) Express your results from (a) in terms of the percent of students who change majors. (Round your answers to two decimal places.) University officials concerned with counseling students are interested in the number of students who change majors rather than the proportion. The university has 38,000 undergraduate students. Convert the confidence Interval you found in (a) to a confidence interval for the number of students who change majors during their college years. (Round your answers to the nearest whole number.) A survey of 1280 student loan borrowers found that 421 had loans totaling more than $20,000 for their undergraduate education. Give a 99% confidence interval tor the proportion of all student loan borrowers who have loans of $20,000 or more for their undergraduate education. (Round your answers to three decimal places.) Lower limit Upper limit One of your employees has suggested that your company develop a new product. You decide to take a random sample of your customers and ask whether or not there is interest in the new product. The response is on a 1 to 5 scale with 1 indicating "definitely would not purchase"; 2, "probably would not purchase"; 3, "not sure"; 4, "probably would purchase"; and 5, "definitely would purchase." For an initial analysis, you will record the responses 1, 2, and 5 as "No" and 4 and 5 as "Yes." What sample size would you use if you wanted the 90% margin of error to be 0.18 or less?. (Round your answer up to the nearest whole number.)Explanation / Answer
1. p=465/985=0.47
z value is 1.96
SE=sqrt(P(1-p)/n)=0.016
Hence R=z*SE=0.03
CI=P+/-E=(0.44,0.50)
b. It is between 44% to 50%
c. Multiply CI with 38000 so range becomes
(16720,19000)
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.