The Law of Or The chances of one event OR another event occurring = the sum of t

Question

The Law of Or The chances of one event OR another event occurring = the sum of the chances of each event separately. Let's call the first event E1, and the second event E2. In this case, let's make E1 the probability of winning the toaster, and E2 the probability of winning the washer-dryer. We can now abbreviate these P(E1) and P(E2) for the probability of event 1, and the probability of event 2. If the game show runs another contest where you can win the prize by picking a ticket out of a hat and your chances of winning are listed in the table below. The probabilities in this problem are given as percentages. That means if the hat contains one hundred pieces of paper in it, then it will have 9 pieces of paper labeled "toaster", 8 pieces of paper labeled "washer-dryer", 1 pieces of paper labeled "vacation" and 82 pieces of paper labeled "pet rock". If the game show ran the contest again using the following probabilities, what would be the chances of winning any prize other than the tropical vacation? Report answer as a percent, not as a decimal. In other words, if it's 55%, report it as 55, not 0.55.

Explanation / Answer

E1 : Event of winning Toaster ; P(E1) = 9%

E2 : Event of winning Washer-dryer; P(E2) = 8%

E3 :Event of winning Vacation'P(E3) = 1%

E4: Event of winning Petrock P(E4) =82%

Probability of winning any prize other than Vacation i.e probability of winning Toaster or washer-dryer or petrock

i.e P(E1 or E2 or E4)

P(E1 or E2 or E4) = P(E1) + P(E2) + P(E4) = 9+8+82 =99

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