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If event A and event B are mutually exclusive, and given P(A) = 0.123, and P(B)

ID: 3177643 • Letter: I

Question

If event A and event B are mutually exclusive, and given P(A) = 0.123, and P(B) = 0.4565, find (a) What is p (A and B) = ? (b) What is P (A or B) =? A couple plans to have children, list all the different possible outcomes according to the sex of each child. Assume that these outcomes an equally likely, find a) What is the probability of getting all girls? b). What is the probability of getting at least 1 child of each Explain clearly the difference between a combination and permutation. New Jersey has 14 four-year colleges. Joe wants to apply to 3 of the many different ways can he select 3 colleges to apply to?

Explanation / Answer

Q.6 P(A) = 0.123 and P(B) = 0.456

if A and Bare mutually exclusive events.

then (i) P(A and B) = 0 because both can't happen same time

(ii) P(A or B) = P(A) + P (B) = 0.123 + 0.456 = 0.579

Q.7 all possibl outcomes are (3G,0B) , (2G,1B) , (1G, 2B) , (0G, 3B) here G are for girls and B for boys

(a) P ( all girs) = 1/4

(b) P( 1child of each) = 2/4 = 1/2

Q.8 When the order doesn't matter, it is combination and when the order does matter, it is permutation. A permutaton is a ordered combination.

Q.9 there are 14 colleges . Joey want to apply for 3 of them. so possible ways to apply = 14C3

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