Suppose you have 3 jars with the following contents. Jar 1 has 4 white balls and

Question

Suppose you have 3 jars with the following contents. Jar 1 has 4 white balls and 1 black ball. Jar 2 has 2 white balls and 3 black balls. Jar 3 has 2 white balls and 2 black balls. One jar is to be selected, and then 1 ball is to be drawn from the selected jar. The probabilities of selecting the first, second, and third jars are 1/3, 1/2, and 1/6 respectively. Find the probability the ball was drawn from Jar 2, given that the ball is white. What is the probability the ball was drawn from Jar 2, given that the ball is white? (Simplify your answer. Type an integer or a fraction.)

Explanation / Answer

probabilty of white ball =(1/3)*(4/5)+(1/2)*(2/5)+(1/6)*(2/4)=0.55

hence probabilty that ball drawn from jar 2' given ball is white =(1/2)*(2/5)/0.55=20/55 =4/11

pls revert

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