please help with this probablility question Married women. The 2010 American Com
ID: 3178073 • Letter: P
Question
please help with this probablility question
Married women. The 2010 American Community Survey estimates that 47.1% of women ages 15 years and over are married. (a) We randomly select three women between these ages. What is the probability that the third woman selected is the only one who is married? (b) What is the probability that all three randomly selected women are married? (c) On average, how many women would you expect to sample before selecting a married woman? What is the standard deviation? (d) If the proportion of married women was actually 30%, how many women would you expect to sample before selecting a married woman? What is the standard deviation? (e) Based on your answers to parts (c) and (d), how does decreasing the probability of an event affect the mean and standard deviation of the wait time until success?Explanation / Answer
a) probabilty =P(first two not married*third married)=(1-0.471)2*0.471=0.1318
b)probabilty all three are married=(0.471)3 =0.1045
c)expected number= 1/p=1/0.471=2.123
std deviation=((1-p)/p2)1/2 =1.544
d)expected number =1/0.3=3.333
std deviation =((1-0.3)/0.32)1/2 =2.7889
e) decreasing proportion increases mean and std deviaiton
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