Listed below are amounts of strontium-90 (in millibecquerels, or mBq per gram of

Question

Listed below are amounts of strontium-90 (in millibecquerels, or mBq per gram of calcium) in a simple random sample of baby teeth obtained from Pennsylvania residents and New York residents boom after 1979 (based on data from "An Unexpected Rise in Stronbum-90 in U S Deciduous Teeth in the 1990s.") by Manga no. et al. Science of the Total Environment. Vol 317) Use a 0 06 significance level to lest the claim that the mean amount of strontium -90 from Pennsylvania residents is greater than the mean amount from New York residents Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviation are equal Test the given claim using the P-value method and critical value method Test statistic t = -2.840 critical value t = -3.729 P -value >0 27 fail to reject H_0 Test statistic t = -10.265critical value t = -2.476 P -value >0 27 fail to reject H_0 Test statistic t = -3.265 critical value t = -1.923 P -value >0 27 fail to reject H_0 Test statistic t = -2.840 critical value t = -1.923 P -value >0 27 fail to reject H_0 Test statistic t = -3.265 critical value t = -0.984 P -value >0 27 fail to reject H_0 Listed below are body temperatures of four subjects measured at two different times in a day

Explanation / Answer

Below are the computation

Test statistics t = 3.265

for t=3.265 and df=16, p-value = 0.002432

As p-value < 0.005 we reject the null hypothesis

Option (C) is correct

x1(bar) 147.5833 x2(bar) 136.4167 s1 10.63834 s2 5.212892 n1 12 n2 12 SE = sqrt[ (s12/n1) + (s22/n2) ] (s12/n1) 9.4312 (s22/n2) 2.2645 SE 3.42 DF = (s12/n1 + s22/n2)2 / { [ (s12 / n1)2 / (n1 - 1) ] + [ (s22 / n2)2 / (n2 - 1) ] } [ (s12 / n1)2 / (n1 - 1) ] 8.086117 [ (s22 / n2)2 / (n2 - 1) ] 0.466187 (s12/n1 + s22/n2)2 136.789564 DF = 16

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