1. Let X be normally distributed with mean = 20 and standard deviation = 12 2. L
ID: 3178527 • Letter: 1
Question
1. Let X be normally distributed with mean = 20 and standard deviation = 12
2. Let X be normally distributed with mean = 3,900 and standard deviation = 1,900.
a. Find P(X 2) b. Find P(X > 8) c. Find P(8 X 14) d. Find P(14 X 26)2. Let X be normally distributed with mean = 3,900 and standard deviation = 1,900.
a. Find x such that P(X x) = 0.9382. b. Find x such that P(X > x) = 0.025 c. Find x such that P(3,900 X x) = 0.1217 d. Find x such that P(X x) = 0.484Explanation / Answer
> #Let X be normally distributed with mean = 20 and standard deviation = 12 > #a. Find P(X 2) > pnorm(2,20,12) [1] 0.0668072 > #Find P(X > 8) > pnorm(8,20,12,lower.tail = F) [1] 0.8413447 > #Find P(8 X 14) > pnorm(14,20,12)-pnorm(8,20,12) [1] 0.1498823 > # Find P(14 X 26) > pnorm(26,20,12)-pnorm(14,20,12) [1] 0.3829249 > #Let X be normally distributed with mean = 3,900 and standard deviation = 1,900. > #a. Find x such that P(X x) = 0.9382. > qnorm(.9382,3900,1900) [1] 6825.691 > # b. Find x such that P(X > x) = 0.025 > qnorm(.025,3900,1900,lower.tail = F) [1] 7623.932 > # c. Find x such that P(3,900 X x) = 0.1217 > qnorm(0.1217+.5,3900,1900) [1] 4488.902 > # d. Find x such that P(X x) = 0.484 > qnorm(.484,3900,1900) [1] 3823.778
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.