1. A candy company claims that 24% of its plain candies are orange, and a sample
ID: 3178658 • Letter: 1
Question
1. A candy company claims that 24% of its plain candies are orange, and a sample of 200 such candies is randomly selected.
a. Find the mean and standard deviation for the number of orange candies in such groups of 200.
=___
=___(Round to one decimal place as needed.)
b. A random sample of 200 candies contains 31 orange candies. Is this result unusual? Does it seem that the claimed rate of 24% is wrong?
A. No, because 31 is within the range of usual values. Thus, the claimed rate of 24 % is probably wrong.
B. Yes, because 31 is below the minimum usual value. Thus, the claimed rate of 24 % is probably wrong.
C. Yes, because 31 is within the range of usual values. Thus, the claimed rate of 24 % is probably wrong.
D. Yes, because 31 is greater than the maximum usual value. Thus, the claimed rate of 24 % is not necessarily wrong.
2. In a clinical trial of a drug used to help subjects stop smoking, 916 subjects were treated with 1 mg doses of the drug. That group consisted of 34 subjects who experienced nausea. The probability of nausea for subjects not receiving the treatment was 0.0107. Complete parts(a) through(c).
a. Assuming that the drug has no effect, so that the probability of nausea was 0.0107, find the mean and standard deviation for the numbers of people in groups of 916 that can be expected to experience nausea.
The mean is__people. (Round to one decimal place as needed.)
The standard deviation is__people. (Round to one decimal place as needed.)
b. Based on the result from part (a), is it unusual to find that among 916 people, there are 34 who experience nausea? Why or why not?
A. It is unusual because 34 is outside the range of usual values.
B. It is unusual because 34 is within the range of usual values.
C. It is not unusual because 34 is outside the range of usual values.
D. It is not unusual because 34 is within the range of usual values.
c. Based on the preceding results, does nausea appear to be an adverse reaction that should be of concern to those who use the drug?
A. The drug does appear to be the cause of some nausea. Since the nausea rate is quite high (about 4%), it appears to be an adverse reaction that occurs very often.
B. The drug does not appear to be the cause of any nausea.
C. The drug does appear to be the cause of some nausea. Since the nausea rate is still quite low (about 4%), it appears to be an adverse reaction that does not occur very often.
please prove answers!!
Explanation / Answer
a)mean =np=0.24*200=48
std deviation =(np(1-p))1/2 =6.0398
B. Yes, because 31 is below the minimum usual value. Thus, the claimed rate of 24 % is probably wrong.
2)a) mean =np =9.8012
std deviation =(np(1-p))1/2 =3.1139
b)A. It is unusual because 34 is outside the range of usual values.
c)yes option C
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