A company runs a three-day workshop on strategies for working effectively in tea
ID: 3178670 • Letter: A
Question
A company runs a three-day workshop on strategies for working effectively in teams. On each day, a different strategy is presented. Forty-eight employees of the company attend the workshop. At the outset, all 48 are divided into 12 teams of four. The teams remain the same for the entire workshop. Strategies are presented in the morning. In the afternoon, the teams are presented with a series of small tasks, and the number of these completed successfully using the strategy taught that morning is recorded for each team. The mean number of tasks completed successfully by all teams each day and the standard deviation is computed. The results follow.
Day (strategy)
Means
Std. dev.
1
17.25
7.10
2
17.64
14.14
3
17.25
14.03
The researchers did an ANOVA F test of the data and obtained the following results.
Source
Sums of squares
Mean square
F-ratio
Day
1.36
0.68
0.0057
Error
5321.71
118.3
Total
5323.08
The degrees of freedom in the denominator of the F test are
33
12.
3.
Day (strategy)
Means
Std. dev.
Explanation / Answer
Degrees of freedom in the denominator of F test
= Error degrees of freedom
As we know,
Error Mean Square = (Error sum of squares) / (Error Degrees of Freedom)
So,
Error Degrees of freedom
= (Error Sum of Squares) / (Error Mean Square)
= 5321.71 / 118.3
= 45
Hence,
Degrees of freedom in the denominator of F test = 45
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