Can you please validate my answers - specifically part c? TABLE 5 Studentized Ra
ID: 3178739 • Letter: C
Question
Can you please validate my answers - specifically part c?
TABLE 5 Studentized Range Values q for Tukey's HSD Method The number of means 0.05 3.64 4.60 5.22 5.67 6.03 6.33 0.0 5.70 6.98 7.80 8.42 8.9 9.32 0.05 6.33 7.03 0.0 0.05 3.34 4.16 4.68 5.06 5.36 5.6 0.0 4.95 5.92 6.54 7.0 7.37 7.68 5.40 0.05 4.75 0.0 4.76 0.05 4.60 0.0 465 0.05 3.15 3.88 4.9 5.12 0.0 4.48 5.27 6.43 6.67 0.05 0.0 5.97 4.75 0.05 0.0 5.84 0.05 0.0 0.05 0.0 4.08 4.37 0.05 0.0 0.05 0.0 4.70 0.05 0.0 4.74 4.28 4.67 0.05 4.49 4.70 0.0 4.47 0.05 0.0 0.05 2.95 3.58 3.96 423 4.45 4.62 20 4.02. 0.0 4.64 5.02 5.29 5.5 5.69 TABLE 5 (Continued) The number of means c 0.05 2.92 3.53 3.90 4.17 4.37 4.54 24 0.0 3.96 4.55 49 5.17 5.37 5.54 4.46 0.05 30 0.0 0.05 4.70 0.0 0.05 60 0.0 0.05 2.80 20 0.0 0.05 2.77 3.3 3.63 3.86 4.03 4.17 0.0 3.64 4.12 440 4.60 4.76 4.88 SOURCE: ES Pea H. Hart Biometrika Tables for Statistici (Cambridge: C ldge Un Meet 6.58 9.67 5.82 7.94 5.30 6.87 6.37 4.79 4.77 5.84 4.68 5.69 4.99 6.80 9.97 6.00 8.17 5.46 7.05 4.90 5.97 4.8 5.8 5.65 4.63 4.39 5.08 6.99 0.24 6.16 8.37 5.74 5.60 7.2 5.0 6.09 4.92 5.92 4.73 4.47 5.16 7.17 0.48 6.30 8.55 5.72 7.36 6.19 5.0 602 492 455 5.23 7.32 10.70 643 8.7 5.83 7.49 6.56 5.20 6.28 5.10 5.76 4.62 5.29Explanation / Answer
Below are my computations of ANNOVA
As p-value is less than significance level, we reject the null hypothesis.
Tukeys HSD Method,
For treatment = 4, significance level = 0.05 and DF = 30, value of q statistics Q = 3.85
Below is the table
source sum of degrees of mean square F statistic p-value squares SS freedom MS treatment 1247.27 3 415.76 185.92 0.00 error 259.40 116 2.24 total 1506.67 119Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.