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Can you please validate my answers - specifically part c? TABLE 5 Studentized Ra

ID: 3178739 • Letter: C

Question

Can you please validate my answers - specifically part c?

TABLE 5 Studentized Range Values q for Tukey's HSD Method The number of means 0.05 3.64 4.60 5.22 5.67 6.03 6.33 0.0 5.70 6.98 7.80 8.42 8.9 9.32 0.05 6.33 7.03 0.0 0.05 3.34 4.16 4.68 5.06 5.36 5.6 0.0 4.95 5.92 6.54 7.0 7.37 7.68 5.40 0.05 4.75 0.0 4.76 0.05 4.60 0.0 465 0.05 3.15 3.88 4.9 5.12 0.0 4.48 5.27 6.43 6.67 0.05 0.0 5.97 4.75 0.05 0.0 5.84 0.05 0.0 0.05 0.0 4.08 4.37 0.05 0.0 0.05 0.0 4.70 0.05 0.0 4.74 4.28 4.67 0.05 4.49 4.70 0.0 4.47 0.05 0.0 0.05 2.95 3.58 3.96 423 4.45 4.62 20 4.02. 0.0 4.64 5.02 5.29 5.5 5.69 TABLE 5 (Continued) The number of means c 0.05 2.92 3.53 3.90 4.17 4.37 4.54 24 0.0 3.96 4.55 49 5.17 5.37 5.54 4.46 0.05 30 0.0 0.05 4.70 0.0 0.05 60 0.0 0.05 2.80 20 0.0 0.05 2.77 3.3 3.63 3.86 4.03 4.17 0.0 3.64 4.12 440 4.60 4.76 4.88 SOURCE: ES Pea H. Hart Biometrika Tables for Statistici (Cambridge: C ldge Un Meet 6.58 9.67 5.82 7.94 5.30 6.87 6.37 4.79 4.77 5.84 4.68 5.69 4.99 6.80 9.97 6.00 8.17 5.46 7.05 4.90 5.97 4.8 5.8 5.65 4.63 4.39 5.08 6.99 0.24 6.16 8.37 5.74 5.60 7.2 5.0 6.09 4.92 5.92 4.73 4.47 5.16 7.17 0.48 6.30 8.55 5.72 7.36 6.19 5.0 602 492 455 5.23 7.32 10.70 643 8.7 5.83 7.49 6.56 5.20 6.28 5.10 5.76 4.62 5.29

Explanation / Answer

Below are my computations of ANNOVA

As p-value is less than significance level, we reject the null hypothesis.

Tukeys HSD Method,

For treatment = 4, significance level = 0.05 and DF = 30, value of q statistics Q = 3.85

Below is the table

source sum of degrees of mean square F statistic p-value squares SS freedom MS treatment 1247.27 3 415.76 185.92 0.00 error 259.40 116 2.24 total 1506.67 119
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