A pumping station operator observes the demand for water at 4 pm each day can be
ID: 3179941 • Letter: A
Question
Explanation / Answer
a)
P(y=0)=(16+10+19)/103
p(y=1)=(8+17+15)/103
P(y=2)=(3+6+9)/103
P(X=0)=(16+8+3)/103
p(X=1)=(10+17+6)/103
P(X=2)=(19+15+9)/103
b) 0*(3/103)+1*(6/103)+2*(9/103)
c)Basically, two random variables are jointly continuous if they have a joint probability density function.
d) the probabilty is 0
Only 1st four parts.
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