2. suppose that the output table of an Excel ANovA routine contained this Value

Question

2. suppose that the output table of an Excel ANovA routine contained this Value Fcrit. ne. At a 0.05, you would conclude that 5.37 AJ there is not a significant difference in the level means B) the means are not all the same, but the tester set the level of significance lower than o.05. C) the factor in question is not a significant source of variation in the value of the response variable. D) the factor in question is a significant source of variation in the value of the response variable. E) Both B and D 3. Suppose an Anova procedure is designed to determine whether the dosage level of a drug is a significant source of variation in white cell count. if the p-value of the test is 0.006, we should conclude that... A) the average white cell count is about the same for each dosage level. B) dosage level is a source of variation in white cell count. C) one should not take this drug. D) Both A and B. 4. In a randomized block design experiment, a very large p-value for the blocking factor is an indication that A) one should ignore blockheads. B) the blocking factor does not account for much of the observed variation in the response variable. C) the blocking factor accounts for much of the observed variation in the response variable. D) introducing the blocking factor was probably necessary to correctly assess the factor of interest. E) Both Cand D 5. Which of the following is (are) true statement (s) about ANOVA? A) Increasing a decreases Fortical B) A value of F much less than 1contradicts the null hypothesis C) The larger F, the more strongly the sample data contradicts the null hypothesis. D) The larger F, the larger the p-value of the test. E) Both A and C. ll. Single Factor Anova. A financial analyst for a small investment firm collects annual stock return data for 9 firms in the energy industry, 8 firms in the retail industry, and 12 firms in the utilities industry. A portion of the data is shown in the accompanying table. The Anova statistical summary is also given. The question is whether all three sectors. Note that the sa es are not all the same size. a 0.05 the mean return is the same Sector% Return SUMMARY Groups count Sum Average Variance Energy 90.1 10.01111 8.461111 13 Retail 63.3 7.9125 4.544107 15 6.3 7.558182 Utilities 75.6 1. Using correct notation, very clearly and explicitly state the hypotheses of the test. (2 pts)

Explanation / Answer

2. correct ans E

Since B & D both are right; p-value<0.05

3. B.

Since p-value<0.05; so reject H0

4. B

P-value>0.05 cant reject H0

5. True are:

A: increasing alpha decreases F-critical

C: P-value decreases

So ans is E (both A&C)

II. ANOVA:

1. H0: there is no difference between them

Ha: there is difference

2. overall grand mean= (10.01+7.912+6.3)/3=8.07

3. SSE=SS_Within = addition of all individual variabilities = 9*8.46 + 8*4.54 + 12*7.55 = 203.06

We need to have SST,

We subtract SSE from SST to get SSB

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