SPRING 2017 MATH1680.150 MWF Quiz: CH5 Quiz Submit Quiz This Question: 1 pt 4 of

Question

SPRING 2017 MATH1680.150 MWF Quiz: CH5 Quiz Submit Quiz This Question: 1 pt 4 of 20 (0 complete) v rhis Quiz: 20 pts poss Question Help According to a poll, about 14% of adults in a country bet on professional sports. Data indicates that 479% of the adult population in this country is male. Complete parts (a) through (e). (a) Are the events "male" and "bet on professional sports" mutually exclusive? Explain. O A. No. A person can be both male and bet on professional sports at the same time. O B. Yes. A person can be both male and bet on professional sports at the same time. O C. Yes. A person cannot be both male and bet on professional sports at the same time. O D. No. A person cannot be male and bet on professional sports at the same time. (b) Assuming that betting is independent of gender, compute the probability that an adult from this country selected at random is a male and bets on professional sports. P(male and bets on professional sports) (c) Using the result in part (b) compute the probability that an adult from this country selected at random is male or bets on professional sports. a P(male or bets on professional sports) Type an integer or decimal rounded to four decimal places as needed) (d) The poll data indicated that 8.7% of adults in this country are males and bet on professional sports. What does this indicate about the assumption in part (by? O A. The assumption was incorrect and the events are not independent O B. The assumption was correct and the events are independent (e) How will the information in part (d) affect the probability you computed in part (c)? Select the correct choice below and fill in any answer boxes within your choice. O A. P(males or bets on professional sports) ng an Type an integer or decimal rounded to four decimal places as needed.) O B. This information does not affect the probability computed in part (c) or Se Click to select your answer(s) a 5

Explanation / Answer

a) P(female and 5-7 activities) = 71/400 = 0.1775

P(female) = 200/400 = 0.5

P(5-7 activities) = 107/400 = 0.2675

P(female) * P(5-7 activities) = 0.13375

Since, P(female and 5-7 activities) is not equal to P(female) * P(5-7 activities), they are not independent events.

Option-B) No

b) P(male and 0 activities) = 21/400 = 0.0525

P(male) = 200/400 = 0.5

P(0 activities) = 42/400 = 0.105

P(female) * P(5-7 activities) = 0.0525

Since, P(male and 0 activities) is equal to P(male) * P(0 activities), they are independent events.

Option-B) Yes

c) Option-B) Yes

D) Option-A)

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