The table below includes results from polygraph (lie detector) experiments condu

Question

The table below includes results from polygraph (lie detector) experiments conducted by researchers In each case, it was known if the subjected lied or did not lie, so the table indicates when the polygraph test was correct. Use a 0.05 significance level to test the claim that whether a subject lies is independent of the polygraph test indication. Do the results suggest that polygraphs are effective in distinguishing between truth and lies? EEE Click the icon to view the table Determine the null and alternative hypotheses. O A. Ho: Polygraph testing is not accurate 1: Polygraph testing is accurate. O B. Ho: Whether a subject lies is independent of the polygraph test indication. H1: Whether a subject lies is not independent of the polygraph test indication. O C. Ho: Polygraph testing is accurate H1: Polygraph testing is not accurate. O D. Ho: Whether a subject lies is not independent of the polygraph test indication H1: Whether a subject lies is independent of the polygraph test indication Determine the test statistic X2 Round to three decimal places as needed.) Which of the following p-value ranges is appropriate? O A. P-value 0.01 O B. 0.01 P-value 0.05 O C. 0.05 P-value 0.10 value 0.10 O D. Do the results suggest that polygraphs are effective in distinguishing between truth and lies? O A. There is not sufficient evidence to warrant rejection of the claim that polygraph testing is 95% accurate O B. There is not sufficient evidence to w arrant rejection of the claim that whether a subject lies is independent of the polygraph test indication. O C. There is sufficient evidence to warrant rejection of the claim that polygraph testing is 95% accurate. O D. There is sufficient evidence to warrant rejection of the claim that whether a subject lies is independent of the polygraph test indication.

Explanation / Answer

1)option B is correct

2)hence X2stat =6.376

p value =0.0116

3)hence option B is correct

4)option D is correct

Observed O Not lie Yes(lied) Total polygraph(lied) 19 29 48 polygraph(Not lied) 29 15 44 Total 48 44 92 Expected E=rowtotal*column total/grand total Not lie Yes(lied) Total polygraph(lied) 25.043 22.957 48 polygraph(Not lied) 22.957 21.043 44 Total 48 44 92 chi square =(O-E)^2/E Not lie Yes(lied) Total polygraph(lied) 1.458 1.591 3.049 polygraph(Not lied) 1.591 1.736 3.327 Total 3.049 3.327 6.376

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