Consider EXAM-1 points out of 120 points. Suppose you wanted to estimate the ave

Question

Consider EXAM-1 points out of 120 points. Suppose you wanted to estimate the average of EXAM-1 score for the entire class and hence you wanted to collect 10 scores of your classmates (including your score). Say the collected scores from students taking class with you are as follows: 105, 91, 52, 116, 100, 95, 98, 109, 96, (YOUR SCORE HERE). Please include your EXAM-1 score to these 9 scores and make it a total count of 10 scores. Answer the following. my score is 73

1. What is the type of variable for "Exam-1 scores" considered?

2. Which is the best graphical method to sketch this data?

3. What is the range of these scores?

4. What is the median of these scores?

5. What is the (unique) mode (if any) for these scores? (Use NA if mode is not unique or if it does not exist)

6. What is the average of these ten scores?

7. Is this mean obtained above in question 6, a sample mean or population mean?

Explanation / Answer

let say X be the scores of your classmates ( including my score i.e. 73)

X= 105, 91, 52, 116, 100, 95, 98, 109, 96, 73

1 ) Discrete Data can only take certain values.while Continuous Data is data that can take any value (within a range)

clearly our data is descrete variable type

2) histogram is the best graphical method to represent this data

3) range is nothing but the difference between largest value and smallest value.

in our data largest value is 116 and smallest value is 52

so range=116-52 =64

4) median of this score

to calcule median first we rearrnge our data in ascending order

52,73,91,95,96,98,100,105,109 & 116

if data is odd then median is middle value but our data is even so for even data median is equal to sum of two middle value divide by 2

in our data 96 and 98 are middle value

so median = (96+98)/2 = 97

5)mode the value that occurs most frequently in a given set of data. but in our data all observation are unique .so mode is not exist in our data.

6) A average is nothing but calculated "central" value of a set of numbers.

To calculate aerage add up all the numbers, then divide by how many numbers there are.

in our data there are 10 observation

mean=( x1+x2+ . . . +x9+x10)/10

(105+91+ 52+ 116+ 100+ 95+ 98+ 109+ 96+ 73)/10

935/10=93.5

mean=93.5

7) The mean obtained in above quection is sample mean because in our data we considered score of randomly selected students .

if we calculate mean score of entire class then it is considered as a population mean.

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.