Consider your class of 100 students. In the below table, we have scores of 99 st
ID: 3180908 • Letter: C
Question
Consider your class of 100 students. In the below table, we have scores of 99 students falling in their respective score intervals. YOU MUST ADD YOUR EXAM-1 SCORE TO THIS FREQUENCIES TO MAKE IT TO COUNT AS 100 STUDENTS. Note: If you have a score of decimals, say 101.4 on your exam-1, round below to 101. If you got a score of 96.5, round it up to 97 and place yourself in the table of frequencies below. i.e., Round below for scores with decimals less than 0.4 and round up for scores with decimals more than or equal to 0.5. For Example, if John has a score of 92.5 out of 120 on Exam-1, he will have an increase in count of frequency value of fourth class 76 – 100 to 27. my score is 73
Scores Interval Frequency
0 - 60 10
61 – 75 16
76 – 90 24
91 – 105 26
106 – 120 23
1.What is the sample mean of these hundred scores?
2.What is the sum of squares of these hundred scores?
3.What is the sample standard deviation of these hundred scores?
4.What is the sample variance of these hundred scores?
5.If in Exam-1, 62.5% or below scored are considered as failed Exam-1, what is the probability that a student selected at random failed the Exam-1.
6.If in Exam-1, 88% or more scored student is considered as performing well in the course, what is the probability that a student selected at random did not perform well on the Exam-1?
Explanation / Answer
(M . F)
1. µ = F
Total = 30 x 10 + 68 x 16 + 83 x 24 + 98 x 26 + 113 x 23 = 8527
F = 99
Mean = 8527/99
Mean = 86.1313
2 = (F . M2 - n * µ2)/(n-1)
2. F . M2 = 10 x 302 + 16 x 682 + 24 x 832 + 26 x 982 + 23 x 1132
= 791711
4. 2 = (791711 - 99 x 86.13132)/ 98
2 = 584.3828
3. = 24.174
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