A consultant for a large university studied the number of hours per week freshme

Question

A consultant for a large university studied the number of hours per week freshmen watch TV versus the 14 number of hours seniors do. The results of this study follow. Is there enough evidence to show the mean 15 number of hours per week freshmen watch TV is different from the mean number of hours seniors do at alpha = 0.005? For the hypothesis stated above [in terms of seniors-Freshmen]: What is/are the critical value(s)? What is the decision? What is the p-value? Fill in only one of the following statements If the Z table is appropriate, If the t table is appropriate.

Explanation / Answer

p-value is 0.059412

As p-value is greater than significane level of 0.005, we fail to reject null hypothesis. This means there is no significant evidence that there is difference in the means.

x1(bar) 18.1 x2(bar) 11.5 s1 7.874 s2 3.9749 n1 9 n2 5 SE = sqrt[ (s12/n1) + (s22/n2) ] (s12/n1) 6.8889 (s22/n2) 3.1600 SE 3.17 DF = (s12/n1 + s22/n2)2 / { [ (s12 / n1)2 / (n1 - 1) ] + [ (s22 / n2)2 / (n2 - 1) ] } [ (s12 / n1)2 / (n1 - 1) ] 5.932075 [ (s22 / n2)2 / (n2 - 1) ] 2.496346 (s12/n1 + s22/n2)2 100.979208 DF = 12

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