The Downtown Parking Authority of Tampa, Florida, reported the following informa
ID: 3183718 • Letter: T
Question
The Downtown Parking Authority of Tampa, Florida, reported the following information for a sample of 223 customers on the number of hours cars are parked and the amount they are charged.
Convert the information on the number of hours parked to a probability distribution. (Round your answers to 3 decimal places.)
Find the mean and the standard deviation of the number of hours parked. (Do not round intermediate calculations. Round your final answers to 3 decimal places.)
How long is a typical customer parked? (Do not round intermediate calculations. Round your final answers to 3 decimal places.)
Find the mean and the standard deviation of the amount charged. (Do not round intermediate calculations. Round your final answers to 3 decimal places.)
The Downtown Parking Authority of Tampa, Florida, reported the following information for a sample of 223 customers on the number of hours cars are parked and the amount they are charged.
Explanation / Answer
a. The probability distribution of number of hours parked is as follows:
a-2 This is a discrete probability distribution, as the distribution of car parking has been tabulated.
b-1. The mean, mu=E[X]=xi*pi
= 1*0.0852+2*0.1480+3*0.2018+4*0.1928+5*0.1480+6*0.0673+7*0.0224+8*0.1345=4.1344 (ans)
Standard deviation, SD[X]=sqrt Var[X]=Sqrt sigma (X-mu)^2*pi
=Sqrt[ (1-4.1344)^2*0.0852+(2-4.1344)^2*0.1480+(3-4.1344)^2*0.2018+(4-4.1344)^2*0.1928+(5-4.1344)^2*0.1480+(6-4.1344)^2*0.0673+(7-4.1344)^2*0.0224+(8-4.1344)^2*0.1345
=2.0769 (ans)
b-3 From the probability distribution, the highest probability is 0.2018, therefore, mode is 3. Therefore, the typical customer parked for 3 hours.
Number of hours Probability, pi=# of events/total 1 0.0852[19/223] 2 0.1480 3 0.2018 4 0.1928 5 0.1480 6 0.0673 7 0.0224 8 0.1345Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.