Ken baked, frosted, and decorated a rectangular cake for the last Math Club meet
ID: 3186077 • Letter: K
Question
Ken baked, frosted, and decorated a rectangular cake for the last Math Club meeting. The cake was 3 inches high, 12 inches wide, and 16 inches long. He centered the cake on a piece of cardboard whose rectangular top surface had been covered with aluminum foil, as shown in the figure below. 12" 16 14 3" 12 C10 35. Ken used a piece of cardboard large enough to allow the cardboard to extend 2 inches beyond the cake on all sides. What is the area, in square inches, of the aluminum foil that is exposed on the top surtace of the cardboard? A. 60 18 B. 64 8812Explanation / Answer
35. As the card board extends by 2 inches on all sides of the cake, so, the length and width of the exposed surface of the cardboard will increase each by (2+2)=4 inches.
Thus length of top cardboard surface = (16+4) inch
= 20 inch
And width of top surface = (12+4) = 16 inch
Hence, area of the top cardboard surface = l × w
= (20 × 16) sq. inch
= 320 square inch
Area of the bottom surface of cake = (16×12) sq. inch
= 192 sq. inch
Hence, required exposed area of the aluminium foil
= (320-192) = 128 square inch. Option E.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.