Consider the force field F = y2i - x2j = (y2, -x2), and two paths C1 and C2, bot

Question

Consider the force field F = y2i - x2j = (y2, -x2), and two paths C1 and C2, both going from (0, 0) to (1, 4), where C1 is given by x = t, y = 4t2 (0 t 1) and C2 is given by x = t, y = 4t (0 t 1). Then The work done along C1 is more than the work done along C2 The work done along C1 is less than the work done along C2 The work done along C1 is same as the work done along C2 The amount of work done cannot be computed From the answer to the last question one can conclude: F is conservative, since F is path-indepedent F is not conservative, since F is path-depedent F cannot be a force field No such conclusion can be drawn

Explanation / Answer

dear look y=4t2 and y=4t for both distance we have given the limits less then or equal to 1. so as we put any value for let t= 1 in both equations answer is same . its mean the force will also same.....so its c is answer. for 2nd part force is dependant on path cause F=y2-x2 these are the equations for path y=4t2 amd x=t answer is b

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