Speedometer readings for a motorcycle at 12-seconds intervals are given in the t

Question

Speedometer readings for a motorcycle at 12-seconds intervals are given in the table. Estimate the distance traveled by the motorcycle during this time period using the velocities at the beginning of the time intervals. Give another estimate using the velocities at the end of the time periods. 1476

Explanation / Answer

Answer: concept: distance travelled= (speed)*(time) a) For 1st 12 seconds the velocity is 30ft/s: Therefore distance travelled is first 12 sec (d1) = 12*30 ft = 360ft for 13th to 24th sec the velocity is 29ft/s: Therefore distance travelled (d2) = 12*29 ft = 348ft similarly for next 12 sec distance travelled would be (d3) = 12*22 ft = 264 ft d4 = 12*20 ft = 240 ft d5 = 12*22 ft = 264 ft total distance travelled = d1 + d2 + d3 + d4 + d5= (360 + 348 + 264 + 240 + 264)ft = 1476ft(ANS) b) Velocity for first 12 sec -> 29 ft/s D1 = 29 *12 ft = 348ft velocity for next 12 sec -> 22ft/s D2 = 22*12 ft = 264ft velocity for next 12 sec -> 20ft/s D3 = 20*12 ft = 240ft velocity for next 12 sec -> 22ft/s D4 = 22*12 ft = 264ft velocity for next 12 sec -> 30ft/s D5 = 30*12 ft = 360ft total distance travelled = d1 + d2 + d3 + d4 + d5= (348 + 264 + 240 + 264 + 360)ft = 1476ft (ans)

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