Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Help 20%D Tue 5:03 PM mo HW2 STAT 201 [Hint: draw a Venn diagram] Let two events

ID: 3195570 • Letter: H

Question

Help 20%D Tue 5:03 PM mo HW2 STAT 201 [Hint: draw a Venn diagram] Let two events-call them event "A" and event-B"-be mutually exclusive (i.e. disjoint). Further let P(A)-0.19 and P(B) = 0.17; Note: please check submission allowance before submitting your answers A) The probability of either event A or event B occurring is: B) The probability of neither event A or event B occurring is: Let two events-call them event "A" and event "B" - be disjoint. [Hint: draw a Venn diagram.] This implies that: Events A and B cannot be complements of each other O Events A and B must also be independent O Events A and B cannot be independent O Events A and B must also be complements of each other study & chill 12170685583 Study - Piano & Focus & Productivity Meaan Gordon Spotify

Explanation / Answer

Answer to the question is as follows:

1.

P(A) = .19
P(B) = .17
P(A and b) =0, since A and B are disjoint

a. P( A or B) = P(A)+P(B) - P(A and B) = .19+.17-0 = .36
b. P(not A neither B) = 1- P(A or B) = 1-P( A or B) = 1-.36 = .64

2.

If they are disjoint, then P(A and B) = 0 , and since P(A)*P(B)!= 0 in our case the events aren't independent
So, C. Events A and B cannnot be independent is CORRECT