a) 8 (b) 12m (d) 1 68. Let z be a real number. Complementary angles with measure
ID: 3195777 • Letter: A
Question
a) 8 (b) 12m (d) 1 68. Let z be a real number. Complementary angles with measured x6 and 3x 69. Let x be a real number. Supplementary angles with measures 10x +7 and 7x + 3 are respectively 70. Find the measurement of two supplementary angles such that the first angle is 4 times larger than the second 6 and 3x are respectively a 699, 219 (b) 120,60 (c) 78°,12 (d) 72°, 18 (a) 107°,73° (b) 98°,820 (c) 1020,78 (d) 117°,63 angle (a) 36°,144° (b) 45°, 135° (c) 30°, 120 (d) 60°,240° 71. Find the complement of an angle whose measure is 3791 3 (a) 51°42' (b) 52°43' u3 (c) 50°17' 50°43' 72. Perform the calculation 9929-2936, 520 (b) 56"36' (c) 55°53 (d) 102065, 567G, 56 00 -(a) -7xv. 73. In the following graph, the measure of x is: 1855 (3x) 79 1764 - (b) 1866. g o (c) 10° (d) 12 .Explanation / Answer
70 )
sum of two supplementary angels =180
let second angle is x then second angle will be 4x because 4 times larger.
x +4x = 180
5x = 180
x = 36
i.e first angle =4x = 4*36 = 144 and second angle = 36
72)
60 minute = 1 degree
1 minute = 1/ 60 degree
29 minute = 29/60 degree
36 minute = 36 /60 degree
therefore,
79 degree 29 minute - 23 degree 36 minute
= 79 degree + 29/60 degree - (23 degree + 36/60 degree)
=79 degree + 29/60 degree - 23 degree - 36/60 degree
=79 degree - 23 degree + 29/60 degree - 36/60 degree
= 56 degree + (29-36)/ 60 degree
= 56 degree - 7/60 degree
= 55 degree + 1 degree - 7/60 degree
= 55 degree + (60 -7)/60 degree
= 55 degree + 53 / 60 degree
= 55 degree 53 minute
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