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M Home-myW ×? Select DARS ×YM IMS Major 1 YM????-D × YM??????×YM?? r-) cl ???! https://www.mathxl.com/Student/Pla 180270077 ? ???? ?? ??,??R??? ? ?? ?????? STA261 M D,M E,MF Test: Midterm PART 1 - 2018 Spring This Question: 8 pts 6 of 18 (2 complete) The carbon dioxide emissions of a group of nations had a mean of 8.6 and standard deviation of 3.3 a. One country's observation was 15.2. Find and interpret its z-score relative to the distribution of values for the group of nations. b. Another country's observation was 5.4. Find and interpret its z-score. a. Find the z-score for the observation of 15.2 ?(Round to two decimal places as needed.) What does this z-score imply? ? A· The observation 15.2 is not an outier because its z-score is posse. O B. The observation 15.2 is an outlier because its z-score is negative. O C. The observation 15.2 is an outlier because it is greater than 3 standard deviations from the mean. O D. The observation 15.2 is not an outier because it is less than 3 standard deviations from the mean. b. Find the z-score for the observation of 5.4 z(Round to two decimal places as needed.) What does this z-score imply? O A. The observation 5.4 is an outlier because it is greater than 3 standard deviations from the mean. O B. The observation 5.4 is not an outlier because its z-score is O C. The observation 5.4 is an outier because its z-score is negative O D. The observation 5.4 is not an outlier because it is less than 3 standard devistions from the mean positive Click to select your answer(s). acBook AirExplanation / Answer
a)
mean = 8.6 , s = 3.3 , x = 15.2
z = ( x -mean) / s
= ( 15.2 - 8.6)/3.3
= 2
z score imply answer is Option D)
b)
x = 5.4
z = ( x -mean) / s
= (5.4 - 8.6)/3.3
= -0.97
z score imply answer is Option D)
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