This is from my Nutrition class, please help me out I\'m lost 1. Oxidation of 1

Question

This is from my Nutrition class, please help me out I'm lost

1. Oxidation of 1 g carbohydrate, fat and protein yields 0.56, 1.07 and 0.42 g metabolic water respectively. Retention of 1 g of dietary protein yields 0.16 g metabolic water whereas 0.07 g and 0.60 g of water is produced when 1 g of dietary fat and carbohydrate, respectively, are retained as fat For a lactating cow consuming 15 kg DM/day and feed contains 76% carbohydrate, 4% fat and 14% crude protein; How much metabolic water will the cow produce under the following scenarios: (i) If 65% of carbohydrate, 70% fat and 60% crude protein is oxidized? (ii) If 15% of crude protein, 15% fat and 12% carbohydrate is retained?

Explanation / Answer

The total given quantity is Q = 15 kg. That shall help us work with the required values.

Carbohydrate = 76% of 15kg = 11.4 kg

Fat = 4% of 15kg = 0.6 kg

Crude Protein = 14% of 15kg = 2.1 kg

These values shall be used as the basis for calculating further percentages

(i) We first evaluate the quantities being oxidized

65% of carbohydrate = 65% of 11.4 kg = 7.41 kg or 7410 g

70% of fat = 70% of 0.6 kg = 0.42 kg or 420 g

60% of crude protein = 60% of 2.1 kg = 1.26 kg or 1260 g

Now using the given oxidation rates, we get

Total metabolic water produced = 7410 x 0.56 + 420 x 1.07 + 1260 x 0.42 = 5128.2 g

(ii) Similarly I will quickly work out this one

15 % of crude protein = 315 g

15% of fat =  90 g

12% of carbohydrate = 1368 g

Again using the given retention rates, we get

Total metabolic water produced = 315 x 0.16 + 90 x 0.07 + 1368 x 0.6 = 877.5 g

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