The Snack Shack sells two snack packs. Pack 1 contains a candy bar and one piece
ID: 3199103 • Letter: T
Question
The Snack Shack sells two snack packs. Pack 1 contains a candy bar and one piece of fruit for? $5. Pack 2 contains two candy bars and three pieces of fruit for? $12. On a given? day, the Snack Shack has 70 candy bars and 90 pieces of fruit. They can sell every snack pack they prepare. How many of each type of pack should they prepare in order to maximize? revenue? Choose the option that could be used to solve the problem. Let x represent the number of Pack 1 snack packs prepared and let y represent the number of Pack 2 snack packs prepared.
A.
Max R? = 5x? + 12y
Subjust to
x plus y less than or equals 90x+y?90
2 x plus 3 y less than or equals 702x+3y?70
x greater than or equals 0 comma y greater than or equals 0x?0, y?0
B.
Max R? = 5x? + 12y
Subjust to
x plus y less than or equals 70x+y?70
2 x plus 3 y less than or equals 902x+3y?90
x greater than or equals 0 comma y greater than or equals 0x?0, y?0
C.
Max R? = 5x? + 12y
Subjust to
x plus 2 y less than or equals 70x+2y?70
x plus 3 y less than or equals 90x+3y?90
x greater than or equals 0 comma y greater than or equals 0x?0, y?0
D.
Max R? = 12x? + 5y
Subjust to
x plus y less than or equals 70x+y?70
2 x plus 3 y less than or equals 902x+3y?90
x greater than or equals 0 comma y greater than or equals 0x?0, y?0
E.
Max R? = 12x? + 5y
Subjust to
x plus 2 y less than or equals 70x+2y?70
x plus 3 y less than or equals 90
Explanation / Answer
pack 1 (x) contains one candy bar and one piece of fruit for 5$
pack 2 (y) contains two candy bars and three peices of fruit for 12$
Total candy bars = 70 and total fruits = 90
So we have for candy bars constraint : 1x + 2y <= 70
for fruits we have 1y + 3y <= 90
Revenue (is to be maximised) is = 5 * x + 12 * y
Thus, problem is maximise 5x+ 12y
x+ y <= 70 and
x+ 3y < = 90
and x, y have to be non negative so x>=0 and y>=0 ;
Thus, option C is the correct answer.
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