It is the second time to post this question cuz some parts from the first andwer

Question

It is the second time to post this question cuz some parts from the first andwere wrong Can someone answer it with details please Hwy01 (1)pdf 100% 18 18.6 20.2 20.0 20.0 20.3 18.9 18 20.00 20.5 19.2 19 20.1 20.7 19.6 20.2 20.8 20.1 21 20.9 20.3 20.5 21.0 20,4 22.5 20.7 21.0 204 23.3 20.7 21.0 20.8 20.6 21.0 21.1 21.5 25 25 21.6 25.4 21.6 26.2 21.7 23.6 264 a. Compute the mean measurement for each method. b. Compute the median measurement for each method. c. Compute the 20% tiimmed mean measurement for each method. d. Compute the first and third quartiles for each method. e. Compute the standard deviation of the measurements for each method. f For which method is the standard deviation the largest? Why should one expect this method to have the largest standard deviation? g other things being equal, is it better for a measurement method to have a smaller standard deviation or a larger standard deviation? or doesn't it matter? Explain. h. If the measurements for one of the methods were converted to inches inch 2.54 cm), how would this affect the mean? The median? The quartiles? The standard deviation?

Explanation / Answer

Ans a- e are given in the above table using excel. The formula for mean is =average(   ), median is =median(   ), quartile is =quartile( array, 1 or 3) and standard deviation is stdev()

f) For the 1st or A method the standard deviation is the highest. This method has highest standard deviation because there is much variation in the data compared to others

g)Measurement methods should have low standard deviation or variation so that the results are consistent

h) The units will not effect mean. However, the median and quartiles will be divided by 2.54. Also the standard deviation will be divided by 2.54

A B C D Mean 22.77 20.76 21.06 20.81 Median 23.65 20.45 21 20.7 1st Quartile 20.75 19.975 20.775 20.175 3rd Quartile 25 22 21.5 21.175 Standard Deviation 2.82 1.41 0.47 0.72

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