Another group of 225 Americans was asked \"Which is your dominant hand your left

Question

Another group of 225 Americans was asked "Which is your dominant hand your left, your right or both/neither?'' The results of this survey are shown below: This group believes that 87% of Americans are right handed, 10% are left handed, and 3% are ambidextrous (corresponding to "Both/Neither"). Test the relevant hypothesis at sigma = 0.05 using Pearson's test. Be sure to show H_0, H_A, the test-statistic, the p-value, your decision, and your conclusion in terms of the problem. What hypothetical percentages for the null hypothesis would result in a test-statistic of zero? Show the percentages for each group

Explanation / Answer

a) null hypothesis: H0: dominant hand % are 87% for right handed , 10% for left and 3% for ambidextrous people

alternate hypothesis:Ha :dominant hand % are not equal to 87% for right handed , 10% for left and 3% for ambidextrous people

here test stat chi square X2 =1.55

for which p value =0.46

as p value is significantly higher then 0.05 level, we can not reject the null hypothesis that dominant hand % are 87% for right handed , 10% for left and 3% for ambidextrous people.

b) for % in proportion to count will result into test stat 0.those are given in corresponding column of observed values.

observed Expected Chi square design P O E=total*p =(O-E)^2/E right 87% 202 195.75 0.20 left 10% 18 22.5 0.90 both/neither 3% 5 6.75 0.45 225 225 1.55

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